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1 ## DBsubject('Algebra') 2 ## DBchapter('Basic Algebra') 3 ## DBsection('Real Numbers') 4 ## KEYWORDS('calculus', 'repeating decimal', 'fractions') 5 ## TitleText1('Calculus: Early Transcendentals') 6 ## EditionText1('2') 7 ## AuthorText1('Rogawski') 8 ## Section1('1.1') 9 ## Problem1('33') 10 ## Author('Carol Panepinto') 11 ## Institution('W.H.Freeman') 12 13 DOCUMENT(); 14 loadMacros("PG.pl","PGbasicmacros.pl","PGanswermacros.pl"); 15 loadMacros("Parser.pl"); 16 loadMacros("freemanMacros.pl"); 17 18 ($r2a, $r2b, $r2ans,$mult, $r2mult, $num, $den, $numr, $denr) = @{ list_random( 19 ['0.2', 6, '4/15', '10', '26.', '24','90', '4', '15'], 20 ['0.', 2, '2/9', '', '22.', '22', '99', '2', '9'], 21 ['0.7', 3, '11/15', '10','73.', '66', '90', '11', '15'], 22 ['0.', 63, '7/11', '', '63.', '63', '99', '7', '11'], 23 ['0.4', 6, '7/15', '10', '46.', '42', '90', '7', '15'], 24 ['0.', 81, '9/11', '', '81.', '81', '99', '9', '11'], 25 ) }; 26 27 Context()->texStrings; 28 BEGIN_TEXT 29 \{ beginproblem() \} 30 \{ textbook_ref_exact("Rogawski ET 2e", "1.1","33") \} 31 $PAR 32 Express the repeating decimal \(r_{1} = 0.\overline{27}\) as a fraction. $SPACE $BBOLD Hint: $EBOLD \(100r_{1} - r_{1}\) is an integer. 33 $PAR 34 \( 0.\overline{27}=\) \{ans_rule(5)\} \(/\) \{ans_rule(5)\}. 35 36 $PAR 37 Then express the repeating decimal \(r_{2} = $r2a\overline{$r2b}\) as a fraction. 38 39 $PAR 40 \( $r2a\overline{$r2b}=\) \{ans_rule(5)\} \(/\) \{ans_rule(5)\}. 41 42 $PAR 43 $BBOLD Note: $EBOLD Enter both fractions in reduced terms. That is, numerator and denominator should have no common factors. 44 45 END_TEXT 46 47 Context()->normalStrings; 48 ANS(Compute("3")->cmp, Compute("11")->cmp); 49 ANS(Compute("$numr")->cmp, Compute("$denr")->cmp); 50 51 Context()->texStrings; 52 SOLUTION(EV3(<<'END_SOLUTION')); 53 $PAR 54 $SOL 55 $PAR 56 Let \(r_{1}=0.\overline{27}\). $SPACE We observe that \(100r_{1}=27.\overline{27}\). $SPACE Therefore \(100r_{1}-r_{1}=27.\overline{27}-0.\overline{27}=99r_{1}\). $BR 57 Then \(r_{1}=\frac{27}{99}=\frac{3}{11}\). 58 $PAR 59 $PAR 60 61 Now let \(r_{2}=$r2a\overline{$r2b}\). $SPACE Then \(100 r_{2}=$r2mult\overline{$r2b}\). $SPACE Therefore \(100 r_{2}-$mult r_2 = $den r_2 = $num\), $BR 62 and \(r_2=\frac{$num}{$den}=\frac{$numr}{$denr}\). 63 64 $PAR 65 END_SOLUTION 66 67 ENDDOCUMENT();
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