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Revision 464 Revision 465
23loadMacros( 23loadMacros(
24"PG.pl", 24"PG.pl",
25"PGbasicmacros.pl", 25"PGbasicmacros.pl",
26"PGchoicemacros.pl", 26"PGchoicemacros.pl",
27"PGanswermacros.pl", 27"PGanswermacros.pl",
28"PGauxiliaryFunctions.pl" 28"PGauxiliaryFunctions.pl",
29"PGgraphmacros.pl"
29); 30);
30 31
31$showPartialCorrectAnswers = 1; 32$showPartialCorrectAnswers = 1;
32 33
33$pi = 4*arctan(1); 34$pi = 4*arctan(1);
45\(x=0\) to \(x=$a\pi\). 46\(x=0\) to \(x=$a\pi\).
46$BR 47$BR
47Hint: Notice that this region consists of two parts. 48Hint: Notice that this region consists of two parts.
48$BR 49$BR
49\{ans_rule(45)\} 50\{ans_rule(45)\}
50$PAR
51END_TEXT 51END_TEXT
52 52
53ANS(num_cmp($ans)); 53ANS(num_cmp($ans));
54 54
55##set $PG_environment{'textbook'} in webworkCourse.ph 55##set $PG_environment{'textbook'} in webworkCourse.ph
59This is similar to Example 1 in Section 5.8 of the text. 59This is similar to Example 1 in Section 5.8 of the text.
60END_TEXT 60END_TEXT
61} 61}
62} 62}
63 63
64$soln_leftx = -0.5;
65$soln_rightx = $b+0.5;
66$soln_boty = -0.5;
67$soln_topy = ($g > $f*sin($b)) ? $g+0.5 : $f*sin($b)+0.5;
68
69$graph = init_graph($soln_leftx,$soln_boty,$soln_rightx,$soln_topy,
70 'axes'=>[0,0],
71 'grid'=>[$soln_rightx-$soln_leftx,$soln_topy-$soln_boty],
72 'size'=>[400,400]);
73plot_functions($graph,FEQ(
74 "$g*cos(x) for x in [0,$b] using color=blue and weight=2"
75 ));
76plot_functions($graph,FEQ(
77 "$f*sin(x) for x in [0,$b] using color=red and weight=2"
78 ));
79
80$graphtext = image(insertGraph($graph));
81
82$soln_fog = $f / $g;
83
84&SOLUTION(EV3(<<'EOT'));
85
86$SOL $BR $BR
87You can examine what this situation looks like by viewing the following graph:
88$BR $graphtext $BR $BR
89
90We note that the functions cross, and we need to calculate that point at which
91they cross, so we can integrate on each side of it separately. We need to do
92those two integrals separately because in the once case one function is
93greater, and in the other case the other function is greater. This matters
94because the integral will need to contain an expression of the difference
95between the functions, so we'll need to know which is greater to decide in what
96order to take that difference. $BR $BR
97
98So we wish to discover the point at which \(y = $g \cos(x)\) crosses
99\(y = $f \sin(x)\). So we set them equal to one another and solve for \(x\):
100 \[
101 \begin{align*}
102 $g \cos(x) = $f \sin(x)
103 &\iff \frac{\cos(x)}{\sin(x)} = \frac{$f}{$g} \\\\
104 &\iff \tan(x) = $soln_fog \\\\
105 &\iff x = \tan^{-1}($soln_fog)
106 \end{align*}
107 \]
108$BR $BR
109
110So then we simply integrate from 0 to \(\tan^{-1}($soln_fog)\) in one section,
111and then from there to \($a\pi\) in another section. For ease of notation,
112let's say \(C = \tan^{-1}($soln_fog)\).
113\[
114\begin{align*}
115 & \int_0^{C} ( $g \cos(x) - $f \sin(x) ) \; dx
116 + \int_{C}^{$a\pi} ( $f \sin(x) - $g \cos(x) ) \; dx \\\\
117=& \left ( $g \sin(x) + $f \cos(x) ) \right|_0^{C}
118 + \left ( $g \sin(x) + $f \cos(x) ) \right|_{C}^{$a\pi} \\\\
119=& $g \sin(C) + $f \cos(C) - $g \sin(0) - $f \cos(0) - $f \cos($a\pi)
120 - $g \sin($a\pi) + $f \cos(C) + $g \sin(C) \\\\
121=& $answer
122\end{align*}
123\]
124
125EOT
126
127
128
64ENDDOCUMENT(); # This should be the last executable line in the problem. 129ENDDOCUMENT(); # This should be the last executable line in the problem.

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