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Fri May 28 14:52:41 2010 UTC (3 years ago) by gage
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```updates to show problem source for model_Calculus_1
```

```    1 ##DESCRIPTION
2 ##  Find the velocity of a ball thrown straight up during periods of time
3 ##  approaching a value, then guess the instantaneous velocity at that point
4 ##ENDDESCRIPTION
5
6 ##KEYWORDS('Calculus')
7 ##Tagged by ynw2d
8
9 ##DBsubject('Calculus')
10 ##DBchapter('Limits and Derivatives')
11 ## DBsection('Tangents, Velocities, and Other Rates of Change')
12 ## TitleText1('Calculus: Early Transcendentals')
13 ## EditionText1('1')
14 ## AuthorText1('Rogawski')
15 ## Section1('2.1')
16 ## Problem1('5')
17 ## TitleText2('Calculus: Early Transcendentals')
18 ## EditionText2('1')
19 ## AuthorText2('Rogawski')
20 ## Section2('2.1')
21 ## Problem2('5')
22
23 DOCUMENT();        # This should be the first executable line in the problem.
24
25 loadMacros(
26 "PG.pl",
27 "PGbasicmacros.pl",
28 "PGchoicemacros.pl",
29 "PGanswermacros.pl",
30 "PGauxiliaryFunctions.pl",
31 "PGcourse.pl"
32 );
33
34 TEXT(beginproblem());
35 \$showPartialCorrectAnswers = 1;
36
37 \$v0 = random(40,100,5);
38 \$t0 = random(1,2,1);
39
40 TEXT(EV2(<<EOT));
41 If a ball is thrown straight up into the air with an initial
42 velocity of \( \$v0 \) ft/s, it height in feet after \( t \)
43 second is given by \( y = \$v0 t - 16 t^2 \).  Find the average
44 velocity for the time period begining when \( t = \$t0 \) and
45 lasting  \$BR (i) \( 0.1 \) seconds
46 \{ans_rule(35) \} \$BR
47 \$BR
48 EOT
49
50 \$ans =\$v0-32*\$t0-16*0.1;
51 ANS(num_cmp(\$ans));
52
53 TEXT(EV2(<<EOT));
54 (ii) \( 0.01 \) seconds
55 \{ans_rule(35)  \} \$BR
56 \$BR
57 EOT
58
59 \$ans =\$v0-32*\$t0-16*0.01;
60 ANS(num_cmp(\$ans));
61
62 TEXT(EV2(<<EOT));
63 (iii) \( 0.001 \) seconds
64 \{ans_rule(35)  \} \$BR
65 \$BR
66 EOT
67
68 \$ans =\$v0-32*\$t0-16*0.001;
69 ANS(num_cmp(\$ans));
70
71 TEXT(EV2(<<EOT));
72 Finally based on the above results, guess what the instantaneous
73 velocity of the ball is when \( t =\$t0 \).
74 \{ans_rule(20) \}
75 \$BR
76 EOT
77
78 \$ans =\$v0-32*\$t0;
79 ANS(num_cmp(\$ans, relTol=>3));
80
81 ENDDOCUMENT();        # This should be the last executable line in the problem.
82
```

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