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1 : jj 517 ##DESCRIPTION
2 :     ## Algebra: Trigonometry of right triangles
3 :     ##ENDDESCRIPTION
4 :    
5 :     ##KEYWORDS('algebra', 'trigonometry', 'The law of sines')
6 :    
7 :     ## tcao , PAID on 11-24-2003
8 :    
9 :     ## DBsubject('Trigonometry')
10 :     ## DBchapter('Trigonometric Functions of Angles')
11 :     ## DBsection('The Law of Sines')
12 :     ## Date('6/3/2002')
13 :     ## Author('')
14 :     ## Institution('')
15 :     ## TitleText1('Precalculus')
16 :     ## EditionText1('3')
17 :     ## AuthorText1('Stewart, Redlin, Watson')
18 :     ## Section1('6.4')
19 :     ## Problem1('27')
20 :     DOCUMENT(); # This should be the first executable line in the problem.
21 :    
22 :     loadMacros(
23 :     "PG.pl",
24 :     "PGbasicmacros.pl",
25 :     "PGchoicemacros.pl",
26 :     "PGanswermacros.pl",
27 :     "PGauxiliaryFunctions.pl"
28 :     );
29 :    
30 :     TEXT(beginproblem());
31 :     $showPartialCorrectAnswers = 0;
32 :    
33 :     $b=random(95,105,1);
34 :    
35 :     TEXT(EV2(<<EOT));
36 :     A communication tower (the side CB) is located at the top (the point C) of
37 :     a steep hill.
38 :     The angle of inclination of the hill is 58 degrees. A guy wire is to be
39 :     attached to the top (the point B) of the tower and to the ground (the point A),
40 :     $b m downhill from the base of the tower (the side AC). The angle
41 :     \( \angle BAC \) in the figure is 12 degrees.
42 :     See the graph
43 :     $PAR \{ image("c6s4p27.gif") \} $PAR
44 :     $BBOLD Click on the graph to view a larger graph$EBOLD
45 :     $BR
46 :     Find the length of cable (the side AB) required for the guy wire.
47 :     Your answer is \{ans_rule(15)\} m;
48 :     $BR
49 :     EOT
50 :    
51 :     $ac=180-(90-58);
52 :     $ab=180-$ac-12;
53 :     $ans1=$b*sin($PI*$ac/180)/sin($PI*$ab/180);
54 :    
55 :     ANS(num_cmp($ans1));
56 :    
57 :     ENDDOCUMENT(); # This should be the last executable line in the problem.

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