Parent Directory
|
Revision Log
Rogawski problems contributed by publisher WHFreeman. These are a subset of the problems available to instructors who use the Rogawski textbook. The remainder can be obtained from the publisher.
1 ## DBsubject('Calculus') 2 ## DBchapter('Infinite Series') 3 ## DBsection('Convergence of Series with positive terms') 4 ## KEYWORDS('calculus', 'infinite series', 'series', 'converge', 'convergence', 'comparison test', 'integral test', 'limit') 5 ## TitleText1('Calculus: Early Transcendentals') 6 ## EditionText1('2') 7 ## AuthorText1('Rogawski') 8 ## Section1('10.3') 9 ## Problem1('51') 10 ## Author('Christopher Sira') 11 ## Institution('W.H.Freeman') 12 13 DOCUMENT(); 14 loadMacros("PG.pl","PGbasicmacros.pl","PGanswermacros.pl"); 15 loadMacros("PGchoicemacros.pl"); 16 loadMacros("Parser.pl"); 17 loadMacros("freemanMacros.pl"); 18 $context = Context(); 19 20 $context->variables->add(n=>'Real'); 21 22 $a = Real(random(3, 7, 1)); 23 $b = Real(random(6, 9, 1)); 24 $p = Real(random(3, 7, 1)); 25 $pm1 = $p-1; 26 $p2m1 = 2*$p-1; 27 28 $start = 1; 29 30 31 32 $ch = random(0,1,1); ##0 diverge, 1 converge! LAD 33 34 if ($ch >0) {#converge 35 $answer = "converges"; 36 $type = "convergent"; 37 $wrong = "diverges"; 38 $start = 1; 39 $func = "\frac{\sqrt[$p]{n}}{$a n^2 + $b}"; 40 $bn = "\frac{1}{n^{\frac{$p2m1}{$p}}}"; 41 $cn = "\frac{n^2}{$a n^2 + $b}"; 42 $pnum = $p2m1; 43 $compare = ">"; 44 45 }else{ 46 $answer = "diverges"; 47 $type = "divergent"; 48 $wrong = "converges"; 49 $start = 1; 50 $func = "\frac{\sqrt[$p]{n}}{$a n + $b}"; 51 $bn = "\frac{1}{n^{\frac{$pm1}{$p}}}"; 52 $cn = "\frac{n}{$a n + $b}"; 53 $pnum = $pm1; 54 $compare = "<"; 55 } 56 57 58 $mc = new_multiple_choice(); 59 60 $mc->qa("Determine convergence or divergence of \( \displaystyle \sum_{n=$start}^{\infty} $func \).", 61 $answer); 62 $mc->extra($wrong); 63 $mc->makeLast("diverges"); 64 65 Context()->texStrings; 66 BEGIN_TEXT 67 \{ beginproblem() \} 68 \{ textbook_ref_exact("Rogawski ET 2e", "10.3","51") \} 69 $PAR 70 \{ $mc->print_q; \} 71 \{ $mc->print_a; \} 72 $BR 73 $BBOLD Note: $EBOLD You are allowed only one attempt on this problem. 74 $PAR 75 END_TEXT 76 Context()->normalStrings; 77 78 ANS(str_cmp($mc->correct_ans)); 79 80 $j1 = 0; 81 82 Context()->texStrings; 83 SOLUTION(EV3(<<'END_SOLUTION')); 84 $PAR 85 $SOL 86 $PAR 87 Apply the Limit Comparison Test with \( a_n = $func \) and \( b_n = $bn \): 88 89 \[ L = \lim_{n\to\infty} \frac{a_n}{b_n} = \lim_{n\to\infty} \frac{$func}{$bn} = \lim_{n\to\infty} $cn = \frac{1}{$a} .\] 90 91 The series \( \displaystyle \sum_{n=1}^{\infty} $bn \) is a $type \(p\)-series \(\left( p = \frac{$pnum}{$p} $compare 1\right) \). Because \( L > 0 \) exists, by the Limit Comparison Test we can conclude that the series \( \displaystyle \sum_{n=1}^{\infty} $func \) also $answer. 92 $PAR 93 END_SOLUTION 94 95 ENDDOCUMENT(); 96 97
| aubreyja at gmail dot com | ViewVC Help |
| Powered by ViewVC 1.0.9 |