Parent Directory
|
Revision Log
Rogawski problems contributed by publisher WHFreeman. These are a subset of the problems available to instructors who use the Rogawski textbook. The remainder can be obtained from the publisher.
1 # DBsubject('Calculus') 2 # DBchapter('') 3 # DBsection('') 4 # KEYWORDS('') 5 # TitleText1('Calculus: Early Transcendentals') 6 # EditionText1('2') 7 # AuthorText1('Rogawski') 8 # Section1('10.5') 9 # Problem1('37') 10 # Author('Emily Price') 11 # Institution('W.H.Freeman') 12 DOCUMENT(); 13 14 15 16 #Load Necessary Macros 17 18 loadMacros("PG.pl", "PGbasicmacros.pl", "PGchoicemacros.pl", "PGanswermacros.pl", ); 19 loadMacros("Parser.pl"); 20 loadMacros("freemanMacros.pl"); 21 22 23 Context()->variables->add(n=>'Real'); 24 25 #Book Values 26 #$rho = 1 27 28 $exp = random(2, 9); 29 $base = random(5,15,1); 30 31 ($an, $den, $result, $L, $compare, $answer, $trueanswer,) = @{list_random( 32 [ "\frac{1}{n^{$exp n}}", "n^{$exp}", "0", Real(0), "<", "converges", 'convergent'], 33 [ "\frac{1}{$base^n}", "$base", "\frac{1}{$base}", Real(1/$base), "<", "converges", 'convergent'] )}; 34 35 36 37 #Let's try to make a multiple choice question 38 $question = new_multiple_choice(); 39 $question->qa(' \( \sum\limits_{n=1}^{\infty} $an \) is:', $trueanswer); 40 $question->makeLast( 'convergent', 'divergent', 'The Root Test is inconclusive'); 41 42 43 Context()->texStrings; 44 45 BEGIN_TEXT 46 \{ beginproblem() \} 47 \{ textbook_ref_exact("Rogawski ET 2e", "10.5", "37") \} 48 $PAR 49 Use the Root Test to determine the convergence or divergence of the given series or state that the Root Test is inconclusive. 50 \[ \sum\limits_{n=1}^{\infty} $an \] 51 \(L = \lim\limits_{n \to \infty} \sqrt[n]{\left| a_n \right|} =\) \{ans_rule()\} (Enter 'inf' for \(\infty\).) 52 $PAR 53 \{ $question->print_q() \} 54 \{ $question->print_a() \} 55 END_TEXT 56 57 Context()->normalStrings; 58 59 #Answer Check Time! 60 ANS($L->cmp); 61 ANS(radio_cmp($question->correct_ans)); 62 63 Context()->texStrings; 64 SOLUTION(EV3(<<'END_SOLUTION')); 65 $PAR 66 $SOL 67 With \( a_n = $an \), 68 \[ \sqrt[n]{a_n} = \sqrt[n]{$an} = \frac{1}{$den} \] and \[ L = \lim_{n \to \infty} \sqrt[n]{a_n} = $result $compare 1. \] 69 Therefore, the series \( \sum\limits_{n=1}^{\infty} $an \) $answer by the Root Test. 70 71 END_SOLUTION 72 73 ENDDOCUMENT()
| aubreyja at gmail dot com | ViewVC Help |
| Powered by ViewVC 1.0.9 |