Difference between revisions of "MatrixAnswer1"
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<b>Setup:</b> |
<b>Setup:</b> |
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+ | Use <code>Context("Matrix");</code>. |
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The MathObject matrices are constructed using the <code>Matrix()</code> constructor. |
The MathObject matrices are constructed using the <code>Matrix()</code> constructor. |
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The matrix A has two rows and three columns, and is constructed by <code>[ [row 1 entries], [row 2 entries] ]</code>, and this construction generalizes in the obvious way. |
The matrix A has two rows and three columns, and is constructed by <code>[ [row 1 entries], [row 2 entries] ]</code>, and this construction generalizes in the obvious way. |
Revision as of 19:46, 28 June 2014
Answer is a Matrix 1
This PG code shows how to evaluate answers that are matrices.
- File location in OPL: FortLewis/Authoring/Templates/LinAlg/MatrixAnswer1.pg
PG problem file | Explanation |
---|---|
Problem tagging: |
|
DOCUMENT(); loadMacros( "PGstandard.pl", "MathObjects.pl", "AnswerFormatHelp.pl", ); TEXT(beginproblem()); |
Initialization: |
Context("Matrix"); $A = Matrix([ [random(-5,5,1),random(-5,5,1),random(-5,5,1)], [random(-5,5,1),random(-5,5,1),random(-5,5,1)], ]); $B = Matrix([random(-5,5,1),random(-5,5,1),random(-5,5,1)]); $answer = $A * ($B->transpose); |
Setup:
Use |
Context()->texStrings; BEGIN_TEXT Suppose \[ A = $A \ \ \mbox{and} \ \ B = $B. \] Evaluate the following matrix product. $BR $BR \( A B^T = \) \{ $answer->ans_array(5) \} \{ AnswerFormatHelp("matrices") \} END_TEXT Context()->normalStrings; |
Main Text:
Use the |
$showPartialCorrectAnswers = 1; ANS( $answer->cmp() ); |
Answer Evaluation: Use standard MathObject answer evaluation. |
Context()->texStrings; BEGIN_SOLUTION ${PAR}SOLUTION:${PAR} Solution explanation goes here. END_SOLUTION Context()->normalStrings; COMMENT('MathObject version.'); ENDDOCUMENT(); |
Solution: |