Difference between revisions of "DraggableProofs"
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(Updates to the draggableproof macro which is now in PG.) |
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+ | <p style="font-size: 120%;font-weight:bold">This problem has been replaced with [https://openwebwork.github.io/pg-docs/sample-problems/Misc/DraggableProof.html a newer version of this problem]</p> |
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<h2>Using Draggable Statements</h2> |
<h2>Using Draggable Statements</h2> |
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Latest revision as of 08:08, 28 June 2023
This problem has been replaced with a newer version of this problem
Using Draggable Statements
This PG code shows how develop a proof with random statements that need to go in the correct order.
- PGML location in OPL: FortLewis/Authoring/Templates/Misc/DraggableProof_PGML.pg
PG problem file | Explanation |
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DOCUMENT(); loadMacros( 'PGstandard.pl', 'MathObjects.pl', 'PGML.pl', 'draggableProof.pl', 'PGcourse.pl' ); TEXT(beginproblem()); |
Details of the draggableProof.pl macro can be found in [the POD]. |
$statements = [ 'Assume \(\sqrt{2}=\frac{a}{b}\) where \(a,b\) are integers, with \(\text{gcd}(a,b)=1\) ', '\(2 = \frac{a^2}{b^2}\)', '\(a^2 = 2b^2\)', 'if \(a^2\) is even, then \(a\) must be even', 'Let \(a=2k\) for \(k\) some integer', 'We can then write \( 2 = \frac{4k^2}{b^2}\) or \(b^2 = 2k^2\)', 'Therefore \(b^2\) is even, so \(b\) is also even', 'If \(a\) and \(b\) are both even, then the initial assumption that \(\text{gcd}(a,b)=1\) is contradicted.', '\(\sqrt{2}\) is therefore not rational.' ]; # These are extra statements that are not needed. $extra = [ 'Then \(a\) is odd', '\(b^2\) cannot be rational.', 'therefore \(a = 2b\)' ]; $proof = DraggableProof( $statements, $extra ); |
The |
BEGIN_PGML [@ $proof->Print @]* END_PGML |
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ANS($proof->cmp); |
Answer Evaluation: |
BEGIN_PGML_SOLUTION Solution explanation goes here. END_PGML_SOLUTION COMMENT('Allows integration in either order. Uses PGML.'); ENDDOCUMENT(); |
Solution: |
- POD documentation: draggableProof.html