MatrixAnswer1

Answer is a Matrix 1

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This PG code shows how to evaluate answers that are matrices.

• File location in OPL: FortLewis/Authoring/Templates/LinAlg/MatrixAnswer1.pg
• PGML location in OPL: FortLewis/Authoring/Templates/LinAlg/MatrixAnswer1_PGML.pg

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PG problem file	Explanation
Problem tagging data	Problem tagging:
DOCUMENT(); loadMacros( "PGstandard.pl", "MathObjects.pl", "AnswerFormatHelp.pl", ); TEXT(beginproblem());	Initialization:
Context("Matrix"); $A = Matrix([ [random(-5,5,1),random(-5,5,1),random(-5,5,1)], [random(-5,5,1),random(-5,5,1),random(-5,5,1)], ]); $B = Matrix([random(-5,5,1),random(-5,5,1),random(-5,5,1)]); $answer = $A * ($B->transpose);	Setup: Use Context("Matrix");. MathObject matrices are constructed using the Matrix() constructor. The matrix A has two rows and three columns, and is constructed by [ [row 1 entries], [row 2 entries] ], and this construction generalizes in the obvious way. If a matrix has only one row, such as B, then it is entered as [row 1 entries] and not as [ [row 1 entries] ]. If $B = Matrix([a,b,c]);, then the matrix $B->transpose is equivalent to Matrix([[a],[b],[c]]); which has an outer pair of brackets enclosing all of the rows, where each row encloses its single element with brackets.
Context()->texStrings; BEGIN_TEXT Suppose \[ A = $A \ \ \mbox{and} \ \ B = $B. \] Evaluate the following matrix product. $BR $BR \( A B^T = \) \{ $answer->ans_array(5) \} \{ AnswerFormatHelp("matrices") \} END_TEXT Context()->normalStrings;	Main Text: Use the ->ans_array(width) method on the MathObject matrix $answer to produce an array of answer boxes each with a specified character width.
$showPartialCorrectAnswers = 1; ANS( $answer->cmp() );	Answer Evaluation: Use standard MathObject answer evaluation.
Context()->texStrings; BEGIN_SOLUTION ${PAR}SOLUTION:${PAR} Solution explanation goes here. END_SOLUTION Context()->normalStrings; COMMENT('MathObject version.'); ENDDOCUMENT();	Solution:

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