Indefinite Integrals | topic started 3/2/2006; 4:11:40 PM last post 3/2/2006; 11:27:50 PM |
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Gavin LaRose - Re: Indefinite Integrals 3/2/2006; 11:27:50 PM (reads: 522, responses: 0) |
Hi Kelly,
A not very elegant solution is to use \(\int x^2\,dx \) = \{ ans_rule(35) \}
This is what I've been doing in this case; a more elegant solution would be to use the Parser explicitly and declare
Cheers, |