I am getting the "Can't solve for adaptive parameters" error for various seeds, such as 4753, 4755.
It seemed to be working fine before the assignment went "live", but I must not have tested enough seeds.
Have tried restricting domains with no success.
I am running WW 2-13, and problem code is as follows:
## DESCRIPTION
## This is Problem 6.1.3-6 from the APEX Calculus text (5.5.3-6 from the ULETH APEX text). It covers indefinite integration using substitution.
## ENDDESCRIPTION
## DBsubject(Calculus - single variable)
## DBchapter(Techniques of integration)
## DBsection(Substitution (without trigonometric functions))
## Level(2)
## Institution('Valdosta State University')
## Author('S. V. Ault')
## RevisedBy('F. J. Francis')
## RevisedBy('T. L. Alderson')
## TitleText1('APEX Calculus')
## AuthorText1('Hartman')
## EditionText1('3.0')
## Section1('6.1')
## Problem1('3-6')
## MO(1)
## Keywords('indefinite integral', 'substitution' ,' antiderivatives ', 'ULETH-MATH1560', 'ULETH-MATH1565')
###########################
# Initialization
DOCUMENT();
# Load whatever macros you need for the problem
loadMacros(
# REQUIRED: Used for basic question and answer operations.
"PGstandard.pl",
# REQUIRED: Used for expression parsing.
"MathObjects.pl",
# Usually required for proper text formatting.
"PGML.pl",
# Used to provide contextual help for how to type answers.
"AnswerFormatHelp.pl",
"parserFormulaUpToConstant.pl",
'contextFraction.pl',
);
sub str {
my $x = shift;
return ( $x > 0 ? '' : '-' )
. ( ($x)**2 == 1 ? '' : abs($x) )
}
# Sets up basic problem information.
TEXT(beginproblem());
#############################
# Setup
#-ULETH-#
Context("Numeric")->noreduce('(-x)-y','(-x)+y)');
Context()->flags->set(reduceConstants=>0);
## (a) ##
$c1 = non_zero_random(-9, 9);
$e1 = random(3,8,1);
$u1 = Formula("x^3 + $c1")->reduce;
$f1 = Formula("3x^2($u1)^{$e1}")->reduce;
## (b) ##
$b2 = random(2, 9, 1)*random(-1,1,2);
$c2 = non_zero_random(-9, 9);
$e2 = random(3,8,1);
$u2 = "x^2 + $b2 x + $c2";
$f2 = Formula("(2x + $b2)($u2)^{$e2}")->reduce;
## (c) ##
$c3 = non_zero_random(-9, 9);
$e3 = random(3,8,1);
$u3 = Formula("x^2 + $c3")->reduce;
$f3 = Formula("x($u3)^{$e3}")->reduce;
## (d) ##
$a4 = random(2, 9, 1)*random(-1,1,2);
$b4 = random(2, 9, 1)*random(-1,1,2);
$c4 = non_zero_random(-9, 9);
$e4 = random(3,8,1);
$bb4 = 4*$a4;
$cc4 = 2*$b4;
$u4 = "$a4 x^2 + $b4 x + $c4";
$f4 = "($bb4 x + $cc4)($u4)^{$e4}";
#### Answers ####
$e1p = $e1 + 1;
$F1 = FormulaUpToConstant("($u1)^{$e1p}/($e1p)")->reduce();
$e2p = $e2 + 1;
$F2 = FormulaUpToConstant("($u2)^{$e2p}/($e2p)")->reduce();
$e3p = $e3 + 1;
$den3 = $e3p * 2;
$F3 = FormulaUpToConstant("($u3)^{$e3p}/($den3)")->reduce();
$a42 = $a4 * 2;
$e4p = $e4 + 1;
Context('Fraction');
$coeff4 = Fraction(2, $e4p)->reduce;
Context('Numeric');
Context()->variables->set(x=>{limits=>[0,1]});
$F4 = FormulaUpToConstant(str($coeff4) . "($u4)^{$e4p}")->reduce();
#-ENDULETH-#
#############################
# Problem Text
#-ULETH-#
BEGIN_PGML
Evaluate the indefinite integrals using Substitution (write your answers in terms of [`x`]).
a) [`\displaystyle\int [$f1] \, dx `] = [___________________________________]{$F1->cmp()} [@ AnswerFormatHelp("formulas") @]*
a) [`\displaystyle\int [$f2] \, dx `] = [___________________________________]{$F2->cmp()}
a) [`\displaystyle\int [$f3] \, dx `] = [___________________________________]{$F3->cmp()}
a) [`\displaystyle\int [$f4] \, dx `] = [___________________________________]{$F4->cmp()}
END_PGML
#-ENDULETH-#
#############################
# Solution
#-ULETH-#
BEGIN_PGML_SOLUTION
Part (a): Substitute [`u = [$u1]`]. Then [`du = 3x^2 \,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int 3x^2 ([$u1])^{[$e1]} \, dx &=&
\displaystyle \int u^{[$e1]} \, du \\
&=& \dfrac{1}{[$e1p]} u^{[$e1p]} + C\\
&=& \dfrac{1}{[$e1p]} ([$u1])^{[$e1p]} + C.
\end{array}
``]<<
Part (b): Substitute [`u = [$u2]`]. Then [`du = (2x + [$b2])\,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int (2x + [$b2])([$u2])^{[$e2]} \, dx &=&
\displaystyle \int u^{[$e2]} \, du \\
&=& \dfrac{1}{[$e2p]} u^{[$e2p]} + C\\
&=& \dfrac{1}{[$e2p]} ([$u2])^{[$e2p]} + C.
\end{array}
``]<<
Part (c): Substitute [`u = [$u3]`]. Then [`du = 2x \,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int x ([$u3])^{[$e3]} \, dx &=&
\displaystyle \dfrac{1}{2}\int u^{[$e3]} \, du \\
&=& \dfrac{1}{2}\cdot\dfrac{1}{[$e3p]} u^{[$e3p]} + C\\
&=& \dfrac{1}{[$den3]} ([$u3])^{[$e3p]} + C.
\end{array}
``]<<
Part (d): Substitute [`u = [$u4]`]. Then [`du = [$a42] x + [$b4] \,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int [$f4] \, dx &=&
\displaystyle \int 2([$a42] x + [$b4])([$u4])^{[$e4]} \, dx \\
&=& \displaystyle 2\int u^{[$e4]} \, du \\
&=& 2\cdot\dfrac{1}{[$e4p]} u^{[$e4p]} + C\\
&=& [$coeff4] ([$u4])^{[$e4p]} + C.
\end{array}
``]<<
END_PGML_SOLUTION
#-ENDULETH-#
#############################
# Answer evaluation
#answer checking is completed in the problem text
#-ULETH-#
# Setting this to 1 means that students will receive feedback on whether their
# answers are correct.
$showPartialCorrectAnswers = 1;
#-ENDULETH#
#############################
# Comments
COMMENT('
Includes a solution set.<BR>
Made from a ULETH template.<BR>
');
ENDDOCUMENT();
## This is Problem 6.1.3-6 from the APEX Calculus text (5.5.3-6 from the ULETH APEX text). It covers indefinite integration using substitution.
## ENDDESCRIPTION
## DBsubject(Calculus - single variable)
## DBchapter(Techniques of integration)
## DBsection(Substitution (without trigonometric functions))
## Level(2)
## Institution('Valdosta State University')
## Author('S. V. Ault')
## RevisedBy('F. J. Francis')
## RevisedBy('T. L. Alderson')
## TitleText1('APEX Calculus')
## AuthorText1('Hartman')
## EditionText1('3.0')
## Section1('6.1')
## Problem1('3-6')
## MO(1)
## Keywords('indefinite integral', 'substitution' ,' antiderivatives ', 'ULETH-MATH1560', 'ULETH-MATH1565')
###########################
# Initialization
DOCUMENT();
# Load whatever macros you need for the problem
loadMacros(
# REQUIRED: Used for basic question and answer operations.
"PGstandard.pl",
# REQUIRED: Used for expression parsing.
"MathObjects.pl",
# Usually required for proper text formatting.
"PGML.pl",
# Used to provide contextual help for how to type answers.
"AnswerFormatHelp.pl",
"parserFormulaUpToConstant.pl",
'contextFraction.pl',
);
sub str {
my $x = shift;
return ( $x > 0 ? '' : '-' )
. ( ($x)**2 == 1 ? '' : abs($x) )
}
# Sets up basic problem information.
TEXT(beginproblem());
#############################
# Setup
#-ULETH-#
Context("Numeric")->noreduce('(-x)-y','(-x)+y)');
Context()->flags->set(reduceConstants=>0);
## (a) ##
$c1 = non_zero_random(-9, 9);
$e1 = random(3,8,1);
$u1 = Formula("x^3 + $c1")->reduce;
$f1 = Formula("3x^2($u1)^{$e1}")->reduce;
## (b) ##
$b2 = random(2, 9, 1)*random(-1,1,2);
$c2 = non_zero_random(-9, 9);
$e2 = random(3,8,1);
$u2 = "x^2 + $b2 x + $c2";
$f2 = Formula("(2x + $b2)($u2)^{$e2}")->reduce;
## (c) ##
$c3 = non_zero_random(-9, 9);
$e3 = random(3,8,1);
$u3 = Formula("x^2 + $c3")->reduce;
$f3 = Formula("x($u3)^{$e3}")->reduce;
## (d) ##
$a4 = random(2, 9, 1)*random(-1,1,2);
$b4 = random(2, 9, 1)*random(-1,1,2);
$c4 = non_zero_random(-9, 9);
$e4 = random(3,8,1);
$bb4 = 4*$a4;
$cc4 = 2*$b4;
$u4 = "$a4 x^2 + $b4 x + $c4";
$f4 = "($bb4 x + $cc4)($u4)^{$e4}";
#### Answers ####
$e1p = $e1 + 1;
$F1 = FormulaUpToConstant("($u1)^{$e1p}/($e1p)")->reduce();
$e2p = $e2 + 1;
$F2 = FormulaUpToConstant("($u2)^{$e2p}/($e2p)")->reduce();
$e3p = $e3 + 1;
$den3 = $e3p * 2;
$F3 = FormulaUpToConstant("($u3)^{$e3p}/($den3)")->reduce();
$a42 = $a4 * 2;
$e4p = $e4 + 1;
Context('Fraction');
$coeff4 = Fraction(2, $e4p)->reduce;
Context('Numeric');
Context()->variables->set(x=>{limits=>[0,1]});
$F4 = FormulaUpToConstant(str($coeff4) . "($u4)^{$e4p}")->reduce();
#-ENDULETH-#
#############################
# Problem Text
#-ULETH-#
BEGIN_PGML
Evaluate the indefinite integrals using Substitution (write your answers in terms of [`x`]).
a) [`\displaystyle\int [$f1] \, dx `] = [___________________________________]{$F1->cmp()} [@ AnswerFormatHelp("formulas") @]*
a) [`\displaystyle\int [$f2] \, dx `] = [___________________________________]{$F2->cmp()}
a) [`\displaystyle\int [$f3] \, dx `] = [___________________________________]{$F3->cmp()}
a) [`\displaystyle\int [$f4] \, dx `] = [___________________________________]{$F4->cmp()}
END_PGML
#-ENDULETH-#
#############################
# Solution
#-ULETH-#
BEGIN_PGML_SOLUTION
Part (a): Substitute [`u = [$u1]`]. Then [`du = 3x^2 \,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int 3x^2 ([$u1])^{[$e1]} \, dx &=&
\displaystyle \int u^{[$e1]} \, du \\
&=& \dfrac{1}{[$e1p]} u^{[$e1p]} + C\\
&=& \dfrac{1}{[$e1p]} ([$u1])^{[$e1p]} + C.
\end{array}
``]<<
Part (b): Substitute [`u = [$u2]`]. Then [`du = (2x + [$b2])\,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int (2x + [$b2])([$u2])^{[$e2]} \, dx &=&
\displaystyle \int u^{[$e2]} \, du \\
&=& \dfrac{1}{[$e2p]} u^{[$e2p]} + C\\
&=& \dfrac{1}{[$e2p]} ([$u2])^{[$e2p]} + C.
\end{array}
``]<<
Part (c): Substitute [`u = [$u3]`]. Then [`du = 2x \,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int x ([$u3])^{[$e3]} \, dx &=&
\displaystyle \dfrac{1}{2}\int u^{[$e3]} \, du \\
&=& \dfrac{1}{2}\cdot\dfrac{1}{[$e3p]} u^{[$e3p]} + C\\
&=& \dfrac{1}{[$den3]} ([$u3])^{[$e3p]} + C.
\end{array}
``]<<
Part (d): Substitute [`u = [$u4]`]. Then [`du = [$a42] x + [$b4] \,dx`].
>>[``
\begin{array}{rcl}
\displaystyle \int [$f4] \, dx &=&
\displaystyle \int 2([$a42] x + [$b4])([$u4])^{[$e4]} \, dx \\
&=& \displaystyle 2\int u^{[$e4]} \, du \\
&=& 2\cdot\dfrac{1}{[$e4p]} u^{[$e4p]} + C\\
&=& [$coeff4] ([$u4])^{[$e4p]} + C.
\end{array}
``]<<
END_PGML_SOLUTION
#-ENDULETH-#
#############################
# Answer evaluation
#answer checking is completed in the problem text
#-ULETH-#
# Setting this to 1 means that students will receive feedback on whether their
# answers are correct.
$showPartialCorrectAnswers = 1;
#-ENDULETH#
#############################
# Comments
COMMENT('
Includes a solution set.<BR>
Made from a ULETH template.<BR>
');
ENDDOCUMENT();